Given: $v = 20$ m/s, $u = 0$ m/s, $t = 5$ s
$$10 = \mu \times 5 \times 9.8$$
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Using Newton's second law of motion: $$F - f = ma$$, where $F$ is the applied force, $f$ is the frictional force, $m$ is the mass, and $a$ is the acceleration.
A block of mass 5 kg is placed on a horizontal surface. A force of 20 N is applied to the block, causing it to move with a uniform acceleration of 2 m/s². What is the coefficient of friction between the block and the surface?